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Tamara says that raising the number i to any integer power results in either -1 or 1 as the result, since i^2 = -1. Do you agreed or disagree with Tamera? Explain

Answer :

jcherry99
I agree only if you have even powers -- even negative ones.

1/i^2 = 1/-1 = - 1
i^0 also gives 1 So far no problem.

It is when you consider the odd numbers that you don't get 1 or -1 
You get either -i or i
i^(4n + 1) =  i
i^(4n - 1) = -i

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