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Zach needs to make a 2.75 m solution of NaOH(molar mass=40.00g/mol) using 350. g of water. What mass of NaOH should he dissolve in the water to make this solution? Please show the steps

Answer :

molality = number of mol solute/ 1000 g solvent = (2.75 mol NaOH)/1000g water


[tex] \frac{2.75( mol NaOH)}{1000(g/ water)} = \frac{x (mol NaOH)}{350(g/water)} [/tex],
[tex]x= \frac{2.75*350}{1000} = 0.963 (mol NaOH) [/tex][tex]0.963 (mol NaOH)* \frac{40.00 (g NaOH)}{1 ( mol NaOH)} =38.5 (g NaOH)[/tex]


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