We have been given a z-score [tex]-0.95[/tex]. We are asked to find the probability of selecting a z score greater than [tex]-0.95[/tex].
We know that normal distribution curve represents area under a z-score. To find the probability of selecting a z-score greater than [tex]-0.95[/tex], we will use following formula.
[tex]P(z>a)=1-P(z<a)[/tex]
[tex]P(z>-0.95)=1-P(z<-0.95)[/tex]
Using normal distribution table, we will find probability of z-score less than [tex]-0.95[/tex].
[tex]P(z>-0.95)=1-0.17106[/tex]
[tex]P(z>-0.95)=0.82894[/tex]
Therefore, probability of a z-score greater than [tex]-0.95[/tex] is 0.8289 and option B is the correct choice.
