Answered

A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function . What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.

equation: -16t^2+50t+10

Answer :

CastleRook
From the model given:
h(t)=-16t^2+50t+10
at the maximum height h'(t)=0
from the function:
h'(t)=-32t+50
thus
-32t+50=0
t=50/32
thus at maximum height:
t=50/32~1.5625
hence, the maximum height will be:
distance=speed*time
distance=1.5625×50
=78.125 ft

Other Questions