Answer :
The distance between 2 points [tex]( x_{1}, y_{1})[/tex] and [tex]( x_{2}, y_{2})[/tex] on the coordinate plane is [tex] \sqrt{(x_{2}-x_{1})^2-(y_{2}-y_{1})^2}[/tex]
So the distance between the given points is [tex]\sqrt{(7-3)^2+(-2-8})^2}= \sqrt{4^2+(-10)^2}= \sqrt{16+100}= \sqrt{116}=10.8 [/tex]
As every unit is 1 mile, so the distance should be 10.8*1=10.8miles.
Hope this helps.
So the distance between the given points is [tex]\sqrt{(7-3)^2+(-2-8})^2}= \sqrt{4^2+(-10)^2}= \sqrt{16+100}= \sqrt{116}=10.8 [/tex]
As every unit is 1 mile, so the distance should be 10.8*1=10.8miles.
Hope this helps.