How many 2-inch by 3-inch by 8-inch bricks will you need to build a (uniformly wide) brick walk with the shape shown in the figure below? (Lay the bricks so that the largest face is up. Assume that a = 10 ft, b = 6 ft, and c = 22 ft.
Here we find the volume of the bricks, will be given by: volume=length*width*height v=2×3×8=48 in³
volume of the bricks is given by: 1 ft= 12 inches thus our dimensions will be: width=10*12=120 in height=6*12=72 in length=22*12=264 in V=120×72×264 V=2,280,960 in³ Thus the number of bricks required will be: 2280960/48 =47520 in³
