Answer :
The lowest and highest wavelengths of this part of the electromagnetic spectrum are:
[tex]\lambda_1 = 200 nm=200 \cdot 10^{-9} m[/tex]
[tex]\lambda_2 = 400 nm=400 \cdot 10^{-9} m[/tex]
The frequency and the wavelenght of an electromagnetic wave are related by
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and f the frequency. By using this equation, we can find the frequencies that corresponds to the lowest and highest wavelengths of this part of the spectrum:
[tex]f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^{-9} m}=1.5 \cdot 10^{15}Hz [/tex]
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^{-9} m}=7.5 \cdot 10^{14}Hz [/tex]
So, the highest frequency associated with this part of the spectrum is the one corresponding to the lowest wavelength:
[tex]f_1 = 1.5 \cdot 10^{15}Hz[/tex]
[tex]\lambda_1 = 200 nm=200 \cdot 10^{-9} m[/tex]
[tex]\lambda_2 = 400 nm=400 \cdot 10^{-9} m[/tex]
The frequency and the wavelenght of an electromagnetic wave are related by
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and f the frequency. By using this equation, we can find the frequencies that corresponds to the lowest and highest wavelengths of this part of the spectrum:
[tex]f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^{-9} m}=1.5 \cdot 10^{15}Hz [/tex]
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^{-9} m}=7.5 \cdot 10^{14}Hz [/tex]
So, the highest frequency associated with this part of the spectrum is the one corresponding to the lowest wavelength:
[tex]f_1 = 1.5 \cdot 10^{15}Hz[/tex]