Answer :
At STP, 1 mol of gas corresponds to 22.4 L. The molar mass of nitrogen is 14.0g so the molar mass of nitrogen gas (N2) is 28.0g. The moles of nitrogen in this sample of nitrogen gas is
28.0 g / (1 mol / 28.0 g) = 1.00 mol
If we convert to liters, we get
(1.00 mol)(22.4 L / 1mol) = 22.4 L
Therefore, your answer is 22.4 L.
28.0 g / (1 mol / 28.0 g) = 1.00 mol
If we convert to liters, we get
(1.00 mol)(22.4 L / 1mol) = 22.4 L
Therefore, your answer is 22.4 L.