Answer:
Part a) [tex]\frac{5}{9}\ \frac{rev}{sec}[/tex]
Part b) [tex]\frac{9}{5}\ \frac{sec}{rev}[/tex]
Explanation:
Part a) what is its frequency, in rev/s
we have that
An old-fashioned LP record rotates at 33 1/3 RPM
so
[tex]33\frac{1}{3}\ \frac{rev}{min}[/tex]
Convert mixed number to an improper fraction
[tex]33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}[/tex]
Remember that
[tex]1\ min=60\ sec[/tex]
Convert rev/min to rev/sec
[tex]\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}[/tex]
Simplify
[tex]\frac{5}{9}\ \frac{rev}{sec}[/tex]
Part b) what is it period, in seconds
we know that
The period is the reciprocal of the frequency
therefore
the frequency is
[tex]\frac{9}{5}\ \frac{sec}{rev}[/tex]
