Answer:
[tex]a=10.8\text{ units}[/tex]
Step-by-step explanation:
To find the length of ''a'' in the given triangle, use the Law of Sines theorem:
Therefore, by the given information:
[tex]\begin{gathered} \frac{\sin120}{a}=\frac{\sin40}{8} \\ \end{gathered}[/tex]
Solve for ''a'':
[tex]\begin{gathered} a=\frac{\sin120*8}{\sin40} \\ a=10.77 \\ \text{ Rounding to the nearest tenth:} \\ a=10.8 \end{gathered}[/tex]
