Answer :
Answer:
The answer is "51.138 N".
Explanation:
please find complete questiuon in the attached file.
[tex]\to m= 21 \ kg\\\\\to h= 0.82 \ m\\\\\to d= 3.3 \ m\\\\[/tex]
The formula for work done:
[tex]mgh = force (f) \times displacement (d)[/tex]
[tex]\to 21(9.8)(0.82) = f(3.3)\\\\\to 168. 756= f(3.3)\\\\\to f = \frac{168. 756}{3.3}\\\\\to f =51.138 \ N \\\\[/tex]
The average force applied to move the object is 51.1 N.
Average force applied
The force applied in moving the object of the given mass must overcome the static frictional force between the object and the surface.
The average force applied is calculated as follows;
P.E = Fs
mgh = Fs
where;
- m is mass of the object given as 21 kg
- h is height of object
- F is average force
- s is displacement
21(9.8)(0.82) = F(3.3)
168.756 = 3.3F
F = 168.756/3.3
F = 51.1 N
The complete question is below:
The mass of the object to be moved is 21 kg, placed at height of 0.82 m on 3.3 m long ramp.
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